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Homework Help: Gauss Law

  1. Mar 1, 2004 #1
    A point charge Q is at the center of a conducting spherical shell of radius R. The total charge of the shell is -Q. (a) What is the field in the region between the point charge and the shell? (b)What is the field outside the shell?

    I think I got part (a): [tex] F = \frac{kq_1 q_2}{r^2} = \frac{kQ(-Q)}{R^2} = -\frac{kQ^2}{R^2} [/tex]
    [tex] E = \frac{F}{Q} = -\frac{kQ}{R^2} [/tex]

    Not quite sure how to do part (b) though.
     
  2. jcsd
  3. Mar 1, 2004 #2
    Try it using Gauss's Law.

    [tex]\int_S \boldsymbol{E}\cdot d\boldsymbol{A} = \frac{Q}{\epsilon_0}[/tex]

    What's the total charge enclosed by a surface surrounding both the shell and the point charge?

    On a similar account, I suggest having another look at part (a). Try it with Gauss's Law! Gauss makes life easy, not hard.

    cookiemonster
     
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