# Gauss law

## Homework Statement

In case of having a conductor (spherically shaped and uncharged) and an irregularly shaped hole inside it with a charge at an arbitrary point, I am asked to find the electric field right outside the conductor sphere.

## Homework Equations

Gauss's law ∫EdA= Q(enclosed) / (a constant)

## The Attempt at a Solution

I assumed that the electric field outside of the conductor is uniform so I had:
E*(4πr^2)= q/ the constant - we can get E from this, but it turns out to be a wrong answer, maybe just taking E to be constant is not correct...

Your answer is almost correct. However, you must remember that E is a vector.
Also, you should note that the electric field is not constant but falls off as $\frac{1}{r^2}$.