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I know i'm reposting this... but no one seems interested in my thread.. maybe becuase it already has replies (which doesn't mean its been solved!) but whatever
cube is placed with its edge at (0,0,0) as in the diagram. The sides of the cube are1 .4m. Find the electric flux and the charge inside the cube if the electric field is given by
a)3yN/C j
b) 4N/C i + [6N/C + (3Nm/C)y]j
for a) [tex] \Phi = \int E \bullet dA \hat{j} [/tex]
[tex] \Phi = \int (3y)(dA) \hat{j} \bullet \hat{j} [/tex]
[tex] \Phi = 3 \int ydA [/tex]
but y is constant and A is constant soo
[tex] \Phi = 3 (1.4)^3 [/tex]
taht gives it for ONE face. But what about hte other face of the cube? I dont want to proceed with the other question since it is similar to this. ANYWAY., if you could help me it would be really awesome
thank you for your help and advice!
cube is placed with its edge at (0,0,0) as in the diagram. The sides of the cube are1 .4m. Find the electric flux and the charge inside the cube if the electric field is given by
a)3yN/C j
b) 4N/C i + [6N/C + (3Nm/C)y]j
for a) [tex] \Phi = \int E \bullet dA \hat{j} [/tex]
[tex] \Phi = \int (3y)(dA) \hat{j} \bullet \hat{j} [/tex]
[tex] \Phi = 3 \int ydA [/tex]
but y is constant and A is constant soo
[tex] \Phi = 3 (1.4)^3 [/tex]
taht gives it for ONE face. But what about hte other face of the cube? I dont want to proceed with the other question since it is similar to this. ANYWAY., if you could help me it would be really awesome
thank you for your help and advice!
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