Gauss units relation

  • Thread starter folgorant
  • Start date
  • #1
29
0
Hi all!

Homework Statement



The problem is:

For a particle with electric charge equal to that of one electron, the trajectory radius R is related to the absolute value of the perpendicular component [tex]P_{\bot}[/tex]of the relativistic moment perpendicular to [tex]\textbf{B}[/tex] from the relation:

[tex]P_{}^{} (MeV/c) = 3.00 \times10^{-4} BR (Gauss \times cm)[/tex]

Homework Equations



I know that:

1Tesla=10^4Gauss
1Coulomb=3x10^9Gauss
1m=10^2cm

The Attempt at a Solution



So:

[tex] \textbf{F}=q\textbf{v}\times\textbf{B}[/tex]

[tex] \textbf{F}_{\bot}=\frac{mv^2}{R}=qvB [/tex]

[tex] \textbf{P}_{\bot}= qBR [/tex]

where on the left side I transform P in MeV/c units obtaining a new value of P,
and on the right side I have qBR initially in Coulomb x Tesla x m.
So

[tex]qBR= (1.6 \times 10^{-19} \times 3\times10^9) (B \times 10^4 )(R \times 10^2)= 4.8 \times 10^{-4} (Gauss^2 \times cm) [/tex]

....who can find the error??? please help!!
 

Answers and Replies

  • #2
pam
455
1
"1Coulomb=3x10^9Gauss" is wrong.
 
  • #3
29
0
precision

okay, it's 1 Coulomb = 3 x 10^9 esu (or Cstat)

but the problem is not solved!!!
 

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