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Gauss units relation

  1. Apr 12, 2008 #1
    Hi all!

    1. The problem statement, all variables and given/known data

    The problem is:

    For a particle with electric charge equal to that of one electron, the trajectory radius R is related to the absolute value of the perpendicular component [tex]P_{\bot}[/tex]of the relativistic moment perpendicular to [tex]\textbf{B}[/tex] from the relation:

    [tex]P_{}^{} (MeV/c) = 3.00 \times10^{-4} BR (Gauss \times cm)[/tex]

    2. Relevant equations

    I know that:

    1Tesla=10^4Gauss
    1Coulomb=3x10^9Gauss
    1m=10^2cm

    3. The attempt at a solution

    So:

    [tex] \textbf{F}=q\textbf{v}\times\textbf{B}[/tex]

    [tex] \textbf{F}_{\bot}=\frac{mv^2}{R}=qvB [/tex]

    [tex] \textbf{P}_{\bot}= qBR [/tex]

    where on the left side I transform P in MeV/c units obtaining a new value of P,
    and on the right side I have qBR initially in Coulomb x Tesla x m.
    So

    [tex]qBR= (1.6 \times 10^{-19} \times 3\times10^9) (B \times 10^4 )(R \times 10^2)= 4.8 \times 10^{-4} (Gauss^2 \times cm) [/tex]

    ....who can find the error??? please help!!
     
  2. jcsd
  3. Apr 12, 2008 #2

    pam

    User Avatar

    "1Coulomb=3x10^9Gauss" is wrong.
     
  4. Apr 13, 2008 #3
    precision

    okay, it's 1 Coulomb = 3 x 10^9 esu (or Cstat)

    but the problem is not solved!!!
     
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