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Gauss's Law and Flux

  • Thread starter dals2002
  • Start date
  • #1
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[SOLVED] Gauss's Law and Flux

ok so i have the biggest question of all i tried solving the following problem:

55.3 million excess electrons are inside a closed surface. What is the net electric flux through the surface?

now i tried the following equations:

[tex]\Phi[/tex]= E . A = Qin/[tex]\epsilon[/tex]

but i have the biggest question when there is excess electron does it mean that the electron field is negative, and if it does then that goes in Qin where then [tex]\Phi[/tex] would be equal to Qin/[tex]\epsilon[/tex], and epsilon being 8.85*10 (permittivity constant)

well any help in solving this problem is very grateful
 
Last edited:

Answers and Replies

  • #2
11
2
You can solve for the enclosed charge, since the elementary charge of an electron (-1.60*10^-19 C) and the number of electrons is known. Just use Q/epsilon to solve for flux.
 
  • #3
12
0
oh wow that was easy, i always see things harder then they are, thanks terbum
 

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