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Gauss's Law and Long wire.

  1. Jul 4, 2008 #1
    1. The problem statement, all variables and given/known data
    Calculate the electric field at a point 2.00 cm perpendicular to the midpoint of a 1.94 m long thin wire carrying a total charge of 4.78 uC.

    Hint: You could integrate BUT if the wire is very long compared to the distance from the wire to where you are calculating the electric field, then the electric field will be radial and Gauss's law might be easier.

    2. Relevant equations

    E = [tex]\frac{kq}{r^2}[/tex]

    where k = 9E9
    q = 4.78E-6
    r = 0.02 m

    E = [tex]\frac{kQx}{(x^2 + a^2)^(3/2)}[/tex]

    3. The attempt at a solution

    First i tried to use the second formula where i made the wire into a circle and used 0.02m as the radius. That didnt work, so i used gauss's formula as the hint suggests, which also didnt work. Suggestions?
  2. jcsd
  3. Jul 4, 2008 #2
    Nevermind, i solved it.
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