# Gauss's Law / Electric Field

jesuslovesu

## Homework Statement

A very large flat aluminum plate of area A has a total charge Q over its surface. The same charge is placed over the upper surface of a glass plate. Compare the electric fields.

## The Attempt at a Solution

I know how to get the electric field of the aluminum plate.
$$\sigma$$ = Q/A
2EA = $$\sigma$$A/e0
E = $$\sigma$$/2e0

For the glass plate, I'm not so sure... Initially I would think E = $$\sigma$$/e0, but it isn't...

## Answers and Replies

Mentor
Realize that the aluminum plate is a conductor.