Gauss's Law / Electric Field

  1. 1. The problem statement, all variables and given/known data
    A very large flat aluminum plate of area A has a total charge Q over its surface. The same charge is placed over the upper surface of a glass plate. Compare the electric fields.


    2. Relevant equations



    3. The attempt at a solution
    I know how to get the electric field of the aluminum plate.
    [tex]\sigma[/tex] = Q/A
    2EA = [tex]\sigma[/tex]A/e0
    E = [tex]\sigma[/tex]/2e0

    For the glass plate, I'm not so sure... Initially I would think E = [tex]\sigma[/tex]/e0, but it isn't...
     
  2. jcsd
  3. Doc Al

    Staff: Mentor

    Realize that the aluminum plate is a conductor.
     
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