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Gauss's Law / Electric Field

  • #1
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Homework Statement


A very large flat aluminum plate of area A has a total charge Q over its surface. The same charge is placed over the upper surface of a glass plate. Compare the electric fields.


Homework Equations





The Attempt at a Solution


I know how to get the electric field of the aluminum plate.
[tex]\sigma[/tex] = Q/A
2EA = [tex]\sigma[/tex]A/e0
E = [tex]\sigma[/tex]/2e0

For the glass plate, I'm not so sure... Initially I would think E = [tex]\sigma[/tex]/e0, but it isn't...
 

Answers and Replies

  • #2
Doc Al
Mentor
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Realize that the aluminum plate is a conductor.
 

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