A hollow spherical conducting shell has a uniformly distributed total surface charge density of -15[tex]\mu[/tex]C/m^2. It's outer surface has a radius R1=0.25m. Its inner radius is R2=0.15 m. A point charge, Q= -6.0[tex]\mu[/tex]C, is placed at the center of the spherical charge. Determine the charge on the inner and outer surfaces of the shell, and show electric field lines.
closed integral E*dA= E(4[tex]\pi[/tex]r^2)= Q/[tex]\epsilon[/tex]
The Attempt at a Solution
since the hollow shell surfaces have a distinguishable inner and outer radius how do I calculate the area? Wouldn't I have to calculate the volume? Please can someone just tell me what the inner and outer charges are. Sorry I am new at using the math format.