- #1

- 13

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter david456103
- Start date

- #1

- 13

- 0

- #2

- 13

- 0

anyone?

- #3

- 2,226

- 9

then apply Gauss's law. the amount of charge inside of the surface is proportional to the length. the area of the outside of the cylinder is proportional to the length and to x. the surface of the cylinder on the two ends (disks with radius x) have no E-fields lines crossing them due to the symmetry argument.

do a little bookkeeping and you'll have an answer for the field strength.

- #4

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

- 11,368

- 1,035

Please be patient. There are rules on this forum regarding the "bumping" of your thread.anyone?

Now, for your question regarding the electric field due to a line of uniform charge at a height x from the line of charge, "Why can we only apply Gauss's law if the line is of infinite length or if x is small compared to the length of the line of charge?"

We

Gauss's law relates the amount of

But since this is the homework section, maybe we should let you tell us why we can only apply Gauss's law to calculate the electric field if the line is of infinite length or if x is small compared to the length of the line of charge?

Share: