Gauss's Law: I need to check this answer

  • #1
DivGradCurl
372
0
A conducting sphere of radius [tex]10 \mbox{ cm}[/tex] has an unknown charge. If the electric field [tex]17 \mbox{ cm}[/tex] from the center of the sphere has the magnitude [tex]3.2 \times 10 ^3 \mbox{N/C}[/tex] and is directed radially inward, what is the net charge on the sphere?

Let:

[tex]R = 10 \mbox{ cm}[/tex]

[tex]r = 17 \mbox{ cm}[/tex]

Gauss's Law:

[tex]Q _{\mbox{Enc}} = \epsilon _0 \Phi = \epsilon _0 \oint \vec{E} \cdot d\vec{A} = -\epsilon _0 EA = -\epsilon _0 E \left( 4 \pi r^2 \right) \approx -3.6 \times 10^{-9} \mbox{ C}[/tex]

Is there anything wrong here? I am not sure.

Any help is highly appreciated.
 

Answers and Replies

  • #2
quantumdude
Staff Emeritus
Science Advisor
Gold Member
5,575
23
I don't have a calculator handy so I can't comment on your numerical answer, but all your other steps are fine.
 

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