Gauss's Law in differential form

Homework Statement

Gauss's Law is often given as:

$$\nabla \cdot \vec{E} = \rho/ \epsilon_0$$

However E is, in general a function of position, so the equation is really
$$\nabla \cdot \vec{E}(\vec{r}) = \rho(\vec{r}) /\epsilon_0$$
correct?

The Attempt at a Solution

Yes. The (r) is often left out, but understood.
Just apply the divrgence theorem to get Gauss's integral law.