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Use Gauss' law to find the charge density on a Van Der Graff dome (r=40cm) if it is charged to 100kV. What is the electric field strength at r=25cm?

I understand gauss's law and I know that I need to use it to find the total charge enclosed on the dome. I can then work out the surface area of the dome and calculate charge density.

If I define a gaussian surface to be a sphere outside the dome, I can work out the charge enclosed if i know the electric field at the gaussian surface. I figure I must use the 100kV given to find the field at the gaussian surface, but I don't understand how.

Also, I need a little help with the second part of the problem. That radius given is inside the dome, unsure of where to go there.

Thanks for any help.

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# Homework Help: Gauss's Law

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