Electric Field of an Infinitely Long Insulating Cylinder

In summary, the problem involves an infinitely long insulating cylinder with a volume charge density that varies with the radius. The magnitude of the electric field at two different radial distances, r<R and r>R, needs to be determined using Gauss's law. The unsuccessful solution involves taking the length l and the mass inside radius r as πr^2 times ρ(r), but this is incorrect and integration is necessary.
  • #1
sicrayan
6
0

Homework Statement


An infinitely long insulating cylinder of radius R has a volume charge density that varies with the radius as given by the following expression where ρ0, a, and b are positive constants and r is the distance from the axis of the cylinder.
symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif

Use Gauss's law to determine the magnitude of the electric field at the following radial distances. (Use the following as necessary: ε0, ρ0, a, b, r, and R.)
(a) r < R
(b) r > R

Homework Equations


gauss's law
 

Attachments

  • symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif
    symimage.cgi?expr=rho%3Drho_0%28a-r%2Fb%29.gif
    565 bytes · Views: 715
Physics news on Phys.org
  • #2
hi sicrayan! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
  • #3
Hi
Thank you for your answer.
My unsuccessful solution:
lets take the length l,
for r<R,
WEyjR.png

why?
 
Last edited:
  • #4
hi sicrayan! :smile:

no, you're taking the mass inside radius r as πr2 times ρ(r) …

it isn't, you need to integrate :wink:
 
  • #5
: ∮E⃗ ⋅dA⃗ = Qenc/ε0
Electric field for a cylindrical charge distribution: E⃗ = (ρ0*r/2ε0)*(1-(a/r)^2) for r < a, E⃗ = ρ0*r/2ε0 for r > a

The electric field of an infinitely long insulating cylinder can be determined using Gauss's law, which states that the electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space (ε0). In this case, the charge enclosed by the surface is the volume charge density (ρ0) multiplied by the volume of the cylinder (πR^2). Therefore, the electric field at any point outside the cylinder (r > R) can be calculated using the formula E = ρ0*r/2ε0, where r is the distance from the axis of the cylinder.

For points inside the cylinder (r < R), the electric field can be calculated using the formula E = (ρ0*r/2ε0)*(1-(a/r)^2), where a is the radius of the cylinder and r is the distance from the axis. This formula takes into account the varying charge density as given in the problem.

Therefore, to determine the magnitude of the electric field at specific radial distances, we can plug in the given values for ρ0, a, b, and R into the above equations. For example, for part (a) where r < R, we can use the formula E = (ρ0*r/2ε0)*(1-(a/r)^2) and plug in the given values to calculate the electric field at that distance. Similarly, for part (b) where r > R, we can use the formula E = ρ0*r/2ε0 and plug in the given values to calculate the electric field at that distance.

In conclusion, the electric field of an infinitely long insulating cylinder can be determined using Gauss's law and the given formula for cylindrical charge distribution. By plugging in the given values, we can calculate the electric field at any radial distance and gain a better understanding of the electric field around the cylinder.
 

What is an electric field?

An electric field is a force field that surrounds electrically charged particles. It is a region in space where a charged particle would experience a force if placed in that space.

How is the electric field of an infinitely long insulating cylinder calculated?

The electric field of an infinitely long insulating cylinder is calculated using the Gauss's Law, which states that the electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space.

What is the direction of the electric field in an infinitely long insulating cylinder?

The electric field in an infinitely long insulating cylinder is directed radially outward from the surface of the cylinder. This means that the electric field lines are perpendicular to the surface of the cylinder at every point.

What is the relationship between the electric field and the charge density in an infinitely long insulating cylinder?

The electric field is directly proportional to the charge density in an infinitely long insulating cylinder. This means that as the charge density increases, the electric field also increases, and vice versa.

How does the electric field vary with distance from an infinitely long insulating cylinder?

The electric field decreases with distance from an infinitely long insulating cylinder. The relationship between the electric field and distance is inverse, meaning that as the distance increases, the electric field decreases. This is because the electric field is spread out over a larger area as the distance increases.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
417
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
11
Views
784
  • Introductory Physics Homework Help
Replies
1
Views
783
  • Introductory Physics Homework Help
Replies
7
Views
984
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
2K
Back
Top