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Gauss's Law

  1. Oct 17, 2004 #1
    I've been thinking about this problem for a while now, and I cant get it to work out. A 9.6X10^-6 C point charge is at the center of a cube with sides of length .5m What is the electric Flux through one of the six faces of the cube? I know the answer is 1.81X10^5 but I cant figure out how to get there. Please Help!!
     
  2. jcsd
  3. Oct 17, 2004 #2

    Tide

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    Hint 1: What would the total flux be through the entire cubic surface?

    Hint 2: Invoke symmetry!
     
  4. Oct 17, 2004 #3
    [tex]\oint {E \cdot dA} = \frac{q}{\epsilon_0}[/tex]

    Let's say B = the area of one side then 6B = A if A is the total surface area so...

    [tex]\oint {E \cdot da} = \frac{q}{\epsilon_0} = 6b \times E[/tex]

    the flux through B is therefore what? (I Realize this isn't entirely correct because I am assuming E and dA are parallel but the answer remains the same through symmetry)
     
    Last edited by a moderator: Oct 17, 2004
  5. Oct 17, 2004 #4
    sure is easy when you figure it out... thanks for the help
     
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