Gauss's Law

  • Thread starter iRaid
  • Start date
  • #1
559
8
Hey everyone,
I was wondering if someone could explain Gauss's law. For whatever reason, I just cannot grasp this idea (might be my teacher). I understand that the electric field through a surface can be represented as [itex]\oint \vec{E} d\vec{A}[/itex] but every problem that we do ends up resulting in it equaling [itex]E\oint dA[/itex] and finally EA. I really don't even understand this equation, how to use it, how to apply it, etc. If anyone could clear this up that'd be great.

Thanks.
 

Answers and Replies

  • #2
guass law: the total flux through a surface is (1/[itex]\epsilon[/itex]) times the total charge enclosed within it .. we take integral of E.ds to arrive to a equation ie [itex]\phi[/itex] = q/[itex]\epsilon[/itex] .
while integrating consider a point charge and make a guassian surface of a sphere, and you will find that kq/r2*4∏r2. now this 4∏r2 gets cancelled with your k and r2... hence we take integral of that to arrive at equation.
 
  • #3
Claude Bile
Science Advisor
1,471
19
The integral form of Gauss's Law is used to work out the charge enclosed by a surface by integrating the electric flux over that surface.

The reason E can frequently be taken outside the integral is that Gauss's Law is independent of the chosen surface. So it makes sense to choose a surface with nice symmetry that makes the integral as simple as possible.

Claude.
 

Related Threads on Gauss's Law

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
9
Views
6K
  • Last Post
5
Replies
115
Views
10K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
0
Views
2K
  • Last Post
Replies
1
Views
1K
Top