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awesome220
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Can anyone help me with this?
If gcd(r,s)=1 then prove that gcd(r^2-s^2, r^2+s^2)=1 or 2.
i'm so confused.
If gcd(r,s)=1 then prove that gcd(r^2-s^2, r^2+s^2)=1 or 2.
i'm so confused.
The GCD (Greatest Common Divisor) is the largest positive integer that divides evenly into two or more numbers. It is calculated using the Euclidean algorithm, which involves repeatedly dividing the larger number by the smaller number and using the remainder as the new divisor until the remainder is 0. The last non-zero remainder is the GCD.
GCD is useful in number theory because it helps in simplifying fractions, finding the least common multiple, and determining whether two numbers are relatively prime. It also has applications in cryptography, prime factorization, and modular arithmetic.
Yes, the GCD can be calculated for any number of integers. The process involves finding the GCD of the first two numbers, and then finding the GCD of that result with the third number, and so on until all numbers have been considered. This is known as the iterative Euclidean algorithm.
The GCD and LCM (Least Common Multiple) are two sides of the same coin. The GCD is the largest number that divides evenly into two or more numbers, while the LCM is the smallest number that is divisible by two or more numbers. Their relationship can be described by the formula: GCD(a,b) * LCM(a,b) = a * b.
No, the GCD of two numbers cannot be greater than both numbers. The GCD is always a factor of both numbers, so it must be less than or equal to the smaller number. For example, the GCD of 12 and 18 is 6, which is a factor of both numbers and is less than both numbers.