- #26

Dick

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i need to get rid of the x ,x is the length of the chain hanging over the edge before the chain starts to move, so when t=O x=b

this gives arccosh(1/1) = 0*sqrt[g/a]

which gives 0 = 0

which doesnt help, then i thought when i intergrated the RHS i should had a constant.

t*sqrt[g/a] + C

so

arccosh(x/b) = t*sqrt[g/a] + C

i dont see how either of these option help me to progress to get

[tex]\\T= \sqrt{\frac{a}{g}} \\ln \frac{a+{\sqrt{ a^2-b^2 }}}{b}[/tex]

Nah. It just says that when t=0 there is b length of chain hanging over the edge. That is the correct initial condition. So putting C=0 for your constant is GOOD. You now want to know when ALL of the chain is hanging over then edge. Then x=?. (Next you'll need a formula for arccosh - then the formula will start looking like you want. You might want to Google 'arccosh' and try to find it!).