I have a picture of two gears, but I need some help with mechanical advantage. Lets say the larger gear is providing the work, and if there was no load supplied to the smaller gear, the large gear be spinning at 1,000 rpm, which would make the small gear spin at 3,000 rpm since the gear ratio is 1:3. Now lets say we add a load of 50lbs resistance to the small gear. Since the small gear is spinning 3 times as fast do we multiply that by 3? To 150lbs. Is that enough data to calculate what would happen to the rpm of the large gear? Even though the small gear is spinning faster, there is 3 times the torque on it because of the gear ratio. So would that cancel out the excess torque and equal increase in speed without the large gear slowing down?..confusing. I know the system would obviously slow down as soon as you add the 50lb load, but the added speed and torque relationship is whats confusing.