I have a question regarding gearing and torque transfer. If I had a receiving stator that requires 3600rpm/26 lb ft torque, and needed to get a drive motor to turn it at those parameters using an 18:1 ratio, what would the drive motor need to be capable of, performance-wise? This will be a real world application, under continuous-use, so longevity will be a large factor. I have formulated 1HP @ 200RPM (1HP X 5252/200=26.26 lb ft), but this is at the drive motor. At 18:1 gearing, the drive motor will be capable of initial torque value required, but as it goes through the gearing, will the torque value increase at 18:1, meaning i can now drop to a different drive motor of approximately 1.45 lb ft/torque (26.26/18=1.4588). I know that the RPM transfers at 18:1, but does the torque do the same? I am trying to determine the drive motor's performance values to apply it into this application. As long as the final drive at the stator is 3600RPM/ 26 lb ft, and gear ratio is a maximum of 18:1 (preferably lower), any advice on what 12V-BLDC motor would fit will be greatly appreciated.