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Geiger counter

  • Thread starter choole
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  • #1
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A particular Gieger counter has a metal cylinder with an inner diameter of 2 cm along whose axis is stretched a wire with 44 N of tension. The potential difference between the wire and the cylinder is 890 volts. The wire has a length of 6 cm and an outer diameter of 1.5 X 10-4 cm.
A. To find the electric field at the surface of wire?
B To find the electric field at the inner surface of the cylinder

Vf - Vi = int(E dot ds) from radius of wire to cylinder.
and E = lemda/2piE0r

i tried solving like this but i didn't get the answer. Please help
 
Last edited:

Answers and Replies

  • #2
Integral
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It is not clear to me what your goal is? What are you looking for?
 
  • #3
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Integral said:
It is not clear to me what your goal is? What are you looking for?
To find the electric field at the surface of the wire?
 

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