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Homework Help: Gene mutation

  1. Apr 24, 2012 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    3. The attempt at a solution

    From what I can see in the data given there must be at LEAST 3 mutations
    I found 5:
    Initial: UCU UAU GGC
    Final: UAU (1 mutation) UUA (2 mutaions) UUG (2 mutations)
    Final: UAU (1 mutation) CUU (2 mutaions) UUG (2 mutations)

    The answer given is:

    Firstly UAC = 2 mutations so total of 6 mutations
    secondly how is this a two single base mutation?

  2. jcsd
  3. Apr 26, 2012 #2
    For the answer given for leucine (UCU) going to tyrosine (UAC), there would need to be one single base mutation from C -> A and U -> C. There is two single base mutations.

    For tyrosine (UAU) going to leusine (UUA), there would need to be a single base mutation in A in tyrosine mutating to U, and the last U in tyrosine mutating to A. That's two single base mutations.

    I think you can figure the last one out if it is GGU mutating to UGG.
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