Okay so i have f(x) I want to find f'(x) it's derivative F'(x) is the slope So lets say they ask for the tangent line to the point on the graph where x=2. I replace x by 2 in my derived equasion and isolate Y. Lets say i found that Y=5 Now I need to find the equasion of the Tangent line. So I replace the coordonates in this equasion: (y-y1)=m(x-x1) I isolate Y and I have my Tangent line. Here's what I don't remember... when they ask me for the general form of the equasion, how do I find that? and also, what's the point of the general form?