Hi Friends, I am getting problem in a geometry problem. Please help me to find the answer. The problem is as follows: AB, BC, CD, AD are the tangent of circle of radius 10 cm. and center O. If the length of BC = 38 cm and CD = 27 cm. Then find the length of AB. Here tangent AB and AD are perpendicular to each other. https://fbcdn-sphotos-d-a.akamaihd.net/hphotos-ak-prn1/s480x480/488010_3019784550925_1195152407_n.jpg ATTEMPT : Here AP=AQ & OP = OQ = 10 cm ∵ ∠ PAQ = 90° ∴ quadrilateral AQOP will be a square ∴ AQ = AP = 10 cm Now, BQ = (x - 10) Now, BQ = BR = (x-10) So, CR = (11 + x) = CS Now, SD = (16 - x) = DP ……. But after this I am unable to complete this. The answer which the book is showing is, x = 21 cm. Please friends help me in finding out the answer. Thank you all in advance.