1. The problem statement, all variables and given/known data On a hot summer day, a young girl swings on a rope above the local swimming hole . When she lets go of the rope her initial velocity is 2.10 m/s at an angle of 35.0 degrees above the horizontal. If she is in flight for 0.615 s, how high above the water was she when she let go of the rope? 2. Relevant equations The equation I used to try to solve for the problem was y=(v0sin(theta))t-.5gt2 3. The attempt at a solution I know the angle is 35 degrees, initial velocity is 2.10 m/s and that initial X and Y positions are both zero. I plug my numbers into the equation given above and get 3.15 for y. The answer in the back of the book says 1.07 meters, but I can't figure out how they arrived at this answer.