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General question about mirrors

  1. May 31, 2008 #1
    [SOLVED] General question about mirrors

    I'll give you a question as an example. My question to you isn't about solving the question, as you'll see below.

    1. The problem statement, all variables and given/known data
    A thumb of height 8cm is held in front of a concave mirror of focal length 10cm. The image formed is 12cm from the vertex of the mirror. Find:
    [I'll give you the one that applies to the question]
    c) the size of the image


    2. Relevant equations
    [tex]\frac{hi}{ho}[/tex] = [tex]\frac{-di}{do}[/tex]


    3. The attempt at a solution
    I plugged in 8cm under ho, 12cm under di, and 60cm under do (calculated previously), and came out with the answer -1.6cm. The answer in the book says it's positive 1.6cm. I've made this mistake previously, and was wondering how I can differentiate between the positive and negative solution.

    Thanks in advance.
     
  2. jcsd
  3. May 31, 2008 #2
    well either your di or your do should be negative because they are on opposite sides of the mirror. its up to you how you make your axes. at least thats what it seems like. id recommend reading the text where you got the equation to see how they define di and do (whether its a distance or displacement).
     
    Last edited: May 31, 2008
  4. May 31, 2008 #3
    But then when finding something like magnification, if the di or do is a negative, then the magnification (formula M= -di/do ) would be a positive number, which ends up being wrong because the image is supposed to be inverted, but ends up erect.

    EDIT: di and do is defined as distance
     
    Last edited: May 31, 2008
  5. Jun 1, 2008 #4

    alphysicist

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    Hi ital dj,

    It might help if you could you post the rest of the problem. With only what's given it leaves a few questions. Like how do you know the image is 12 cm in front of the mirror instead of 12 cm behind?

    More importantly, if part c asked for the size and part d asked for the orientation (erect/inverted), then that would be a good indicator that in part c they were using the word size to mean the magnitude of the height [itex]h_i[/itex].
     
  6. Jun 1, 2008 #5
    I gave you the whole question, the only things I left out were: a) the position of the object; b) what sign should the focal length have; and d) the type and orientation of the image
     
  7. Jun 1, 2008 #6

    alphysicist

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    The question in part d is what I was looking for. When you solve for the height [itex]h_i[/itex], it gives you the size (magnitude of height) and the orientation (from the sign of h).

    In this problem it looks like they split these parts up: they just want the size for part c, and they ask about the orientation (which is just asking about the sign of h) in part d.
     
  8. Jun 1, 2008 #7
    Ok, thanks so far, but how, in general, do I know if the height is going to be positive or general, because I keep ending up with a negative number, but in most of my questions, the answer is a positive number.
     
  9. Jun 1, 2008 #8

    alphysicist

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    I don't believe there are any hard rules; it's a matter of interpreting the question. As a beginning, I would say that the variable [itex]h_i[/itex] can be positive or negative, and we call that variable the height. So when they ask for the height, they are probably are asking for the value with the correct sign [itex]h_i[/itex]. When they ask for the size, length, dimension, etc. I would think they probably mean just the magnitude [itex]|h_i|[/itex].

    But you still have to read and interpret the question carefully to be sure for a specific case.
     
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