- #1

seen

- 2

- 0

it says to find the general solution (y=...)

given y'(x) = 2/(7-4y)

...

how do u get to this:

y = 7/4 +/- √(k-x)

that is: seven over four plus or minus the squareroot of k minus x

k being another constant

please help if u can

thanx