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could some1 help me with the working of this question. it's for homework and i would help if i knew how to come to the answer in the back of the book.
it says to find the general solution (y=...)
given y'(x) = 2/(7-4y)
...
how do u get to this:
y = 7/4 +/- √(k-x)
that is: seven over four plus or minus the squareroot of k minus x
k being another constant
please help if u can
thanx
it says to find the general solution (y=...)
given y'(x) = 2/(7-4y)
...
how do u get to this:
y = 7/4 +/- √(k-x)
that is: seven over four plus or minus the squareroot of k minus x
k being another constant
please help if u can
thanx