- #1
Ad123q
- 19
- 0
I was just wondering, if I had a matrix in reduced-row echelon form, say,
1 0 0 2
0 1 3 1
0 0 0 0
then I could write the general solution as a1= -2a4 , a2= -3a3-a4, with a3 and a4 defined in terms of these. (I obtained this solution by putting a1, a2, a3 and a4 under the first, second, third and fourth columns, equating the matrix to zero, and solving for the unknowns under the leading 1's).
But how would I find the general solution of, say
0 1 0 0
0 0 1 0
0 0 0 1
0 0 0 0 ?
Any help much appreciated.
1 0 0 2
0 1 3 1
0 0 0 0
then I could write the general solution as a1= -2a4 , a2= -3a3-a4, with a3 and a4 defined in terms of these. (I obtained this solution by putting a1, a2, a3 and a4 under the first, second, third and fourth columns, equating the matrix to zero, and solving for the unknowns under the leading 1's).
But how would I find the general solution of, say
0 1 0 0
0 0 1 0
0 0 0 1
0 0 0 0 ?
Any help much appreciated.