the equation

dy[tex]/dx = e^-3y cos x (1+sin x )^2[/tex]

My attempt at a general solution

1[tex]/3 e^3 = (sin x +1)^3 = y =e^3/(sin + 1)^3 +c[/tex]

and the implicit form as

1[tex]/12 (1+sin x )^3/exp (3y)[/tex]

this is harder maths than ive done so not as sure as with most.