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Generalized Binomial Formula

  1. Nov 2, 2008 #1
    I stuck at the second "="...i know it goes like this because the formula...i just someone explain to me why it works like that.

    thank you soooo much!
     

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  2. jcsd
  3. Nov 2, 2008 #2

    HallsofIvy

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    What is the definition of
    [tex]\left(\begin{array}{c} x \\ n \end{array}\right)[/tex]
    when x is not an integer?

    If you cannot answer that, can you say what
    [tex]\left(\begin{array}{c} m \\ n \end{array}\right)[/tex]
    means when m and n are integers? What do you get if you replace the "m" with "x"?
     
  4. Nov 2, 2008 #3
    this is what i've done...still far from the destination

    Sum(0 to infinity) (-1)^n [(1)(3)...(2n-1) x^(n+1/2) / (2n)!]

    donno how to transform x^(n+1/2) to x^(n)?...thank you for your help!
     
  5. Nov 3, 2008 #4

    gabbagabbahey

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    where did the n+1/2 come from???
     
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