In 2 dimensions, is the geodesic deviation equation governed by a single scalar, independent of the direction of the geodesics? That is, if ξ is the separation of two nearby geodesics, do we have [tex]d^2 \xi/ds^2 + R\xi = 0 [/tex] where R is a scalar that is completely independent of the direction of the geodesics?(adsbygoogle = window.adsbygoogle || []).push({});

If so, how can we see that there can be no directional dependence in 2d?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Geodesic deviation in 2d

Loading...

Similar Threads - Geodesic deviation | Date |
---|---|

I Geodesic deviation in static spacetime | Oct 28, 2017 |

I Schutz: question regarding geodesic deviation | Mar 21, 2017 |

Quick one-line working on Geodesic Deviation Equation | Feb 28, 2015 |

Why no absolute derivative in this example of geodesic deviation? | Sep 8, 2014 |

Geodesic deviation in spacetime, not just space | Jun 2, 2014 |

**Physics Forums - The Fusion of Science and Community**