# Geodesic Deviation

1. Jan 24, 2004

### Arcon

2. Jan 24, 2004

### lethe

i took a look at it, and did the calculation. i thought it was pretty straightforward. where did you get stuck? what extra terms do you have?

remember that x is a geodesic. so there is a geodesic equation in x, and it therefore vanishes. and remember that &chi; is very small; drop any term with more than one &chi; in it.

3. Jan 24, 2004

### Arcon

Re: Re: Geodesic Deviation

I fingered it out

One has to drop not only the term &chi*&chi but the term which is the product of &chi and a derivative of &chi. That was what I was missing.

4. Jan 24, 2004

### Arcon

Re: Re: Re: Geodesic Deviation

Thank you

I believe that I've fingered it out

One has to drop not only the term &chi;*&chi; but the term which is the product of &chi; and a derivative of &chi;. That was what I was missing.

Again - thanks for the response

Arcon

5. Jan 25, 2004

### Arcon

Re: Re: Geodesic Deviation

Seems that this small detail (drop term with &chi;d&chi;dT) has always tripped me up in that derivation. I guess I was just blind to it. But now that I know it then the derivation is simple.

Just to make sure I understood the approximation can you check this for me?

http://www.geocities.com/physics_world/gr/geodesic_deviation.htm

I commented on the terms to drop right after Eq. (14) and right after Eq. (15)

Thanks

I don't know how I missed this before but the equation of geodesic deviation clearly shows that tidal forces are velocity dependant!

Arcon