Hello! I am a bit confused about the geodesic equation. So for a massive particle it is given by: ##\frac{d}{d\tau}\frac{dx^\alpha}{d\tau}+\Gamma^\alpha_{\mu\beta}\frac{dx^\mu}{d\tau}\frac{dx^\beta}{d\tau}=0##, where ##\tau## is the proper time, but in general can be any affine parameter. I am confused about ##x^\alpha##. In which coordinate is this measured i.e. where is the observer located. I am actually doing the Schwarzchild metric now, and from the geodesic equation you can get ##\frac{dx^\alpha}{d\tau}##, but I am not sure for who do you get this, as all the values of the geodesic equations are evaluated at the position of the moving object, so for example ##\frac{dt}{d\tau}##, connects the time of the observer, with the proper time of the object, however, different observers, in Schwarzchild metric, measure different times, yet the geodesic equation gives just a value for it. Can someone explain this to me please? Thank you!(adsbygoogle = window.adsbygoogle || []).push({});

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# I Geodesic equation

Have something to add?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**