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we had a a function on a graph of f(x)=1/x and then we are suposed to find the area of a triangle where the tangent line is the hypontenuse, and the x and y axis are the base and hight.....i found f'(x)= -1/x^2

from here i used the formula y-yo=x0(x-x0) and got that the x intercept is 2xo and then got the y intercept to be 2yo which means those are the lengths of the base and the hight, from there you use the formula of a triangle and that is (2)(2)(xo)(yo) all over 2 and then i canceled out the 2's and got 2(xo)(yo) as the area of the triangle...and this all is correct...but how the heck does the also = 2??? apperantly 2(Xo)(Yo)=2....could someone please explain this, possibly just some basic algebra rule and i'm having a brain fart???

by the way, this is off of MIT's OCW.....

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# Geometric derivative problem

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