1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Geometric / Optical Isomers

  1. May 6, 2007 #1
    For the molecule [tex]\textrm{Ni}\left(\textrm{OH}\right)_{2}\textrm{Cl}\left(\textrm{NH}_{3}\right)_{3}[/tex], how do you determine the number of geometric and optical isomers? I first drew the molecule with a central [tex]\textrm{Cl}[/tex] bonded to three [tex]\textrm{NH}_{3}[/tex] molecules and a [tex]\textrm{Ni}[/tex]; the [tex]\textrm{Ni}[/tex] was in turn bonded to two [tex]\textrm{OH}[/tex] molecules. From this, it appeared that no matter how I moved the atoms surrounding the central atom, the configuration would always be the same; it would just be rotated counterclockwise or clockwise.
     
  2. jcsd
  3. May 7, 2007 #2

    chemisttree

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    This is a nickel (III) octahedral complex. Try drawing nickel with a square planar bipyramid around it. There will be four groups in the square plane and two other groups in the axial positions. Switch out the groups to determine how many isomers you have.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Geometric / Optical Isomers
Loading...