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Homework Statement
3,6,12........1536
determine the number of terms in the progression
Homework Equations
The Attempt at a Solution
a=3 r=2
n= ar^n-1
1536= (3) (2)^n-1
1536= (3) (2)^n-1Okay, so solve it! First, divide both sides by 3. If that sequence is actually geometric, you should be able to identify 1536/3 as a power of 2. I suggest you just calculate powers of 2: 1, 2, 4, 8, 16, ... until you get to that number.
There are errors in your work. Also, you need parentheses around your exponent expressions.1536= (3) (2)^n-1
1536/3 = 6^n-1[itex]/[/itex]3
512 = 2^n-1
512 = 2^10-1
512 = 2^9
n = 10
The above is incorrect. 3*2^(n - 1) [itex]\neq[/itex] 6^(n - 1)1536= (3) (2)^(n-1)
1536/3 = 6^n-1[itex]/[/itex]3
The above is also incorrect. [6^(n - 1)]/3 [itex]\neq[/itex] 2^(n - 1)512 = 2^n-1
512 = 2^10-1
512 = 2^9
n = 10