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[itex]\sum^{\infty}_{k=4}[/itex] [itex]\frac{1}{5^{k}}[/itex]
ar^n=a/(1-r)
Here is what I did:
a=5
r=1/625
(1/5)/(1-1/625)=(1/5)/(624/625)=625/3120=125/624
The Answer is 1/500
Where am I going wrong?
ar^n=a/(1-r)
Here is what I did:
a=5
r=1/625
(1/5)/(1-1/625)=(1/5)/(624/625)=625/3120=125/624
The Answer is 1/500
Where am I going wrong?