# Geometric Series

mattmannmf
{sigma} 2*(-1/4)^(n-1)

Could i treat this as a geometric series? i know geometric is in the form of ar^n but the n is (n-1)

my A=2
my r= -1/4

Mentor
$$\sum_{n = 1}^{\infty} 2 (-1/4)^{n - 1}$$

Write a few terms of this series and see if you can adjust the starting index.

mattmannmf
i have no idea what you mean by that

Staff Emeritus
Gold Member
{sigma} 2*(-1/4)^(n-1)

Could i treat this as a geometric series? i know geometric is in the form of ar^n but the n is (n-1)

my A=2
my r= -1/4

You have
2(-1/4)n-1
and you want
A rn-1
?

Why not set them equal and try solving for A and r?

mattmannmf
no... im trying to solve whether or not the series converges or diverges and then i have to determine the sum of the series... meaning where the series sums up to..

Staff Emeritus