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Geometric similarity

  1. May 25, 2016 #1
    1. The problem statement, all variables and given/known data

    in this question , Lm / Lp = 1/ 6 ? or Lp / Lm = 1/6 ? Lp = length of prototype , Lm = Length of model

    Mb4Cvh3.jpg

    2. Relevant equations


    3. The attempt at a solution
    i really have no idea... can someone help please?
     
  2. jcsd
  3. May 25, 2016 #2

    phinds

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    Gold Member
    2016 Award

    If you have no idea at all then the question arises, how do you come to be working on a problem that you have no idea how to answer? What level of school are you in? Where is the problem from? We don't spoon-feed answers here, we try to help you solve a problem yourself, but we need more background to even be able to give you a hint that would be meaningful to you.
     
  4. May 25, 2016 #3
    i am in uni now , and the notes is from my book , IMO , it should be Lp / Lm = 1/6 , am i right ?
    can you help ?
     
  5. May 28, 2016 #4
    i dont think the working provided is correct
    IMO , it should be (Vr)( Lr )= (nu)r

    nu = kinematic viscosity
    since nu is constant , so ,

    Vp / Vm = Lm / Lp
    60 / Vm = 1/6

    so , Vm = 360km/h , am i right ?

    thus , force has formula of ρ(L^3)(velocity) , so force is directly proportional to v ,

    Fp / Fm = Vp / Vm
    Fp / 250 = 60/360 , Fp = 41.7N , is it correct ?
     
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