- #1

First I will post my question.

ABC is an equilateral triangle, and P is a point on the smaller arc BC of the cirumcircle of the triangle ABC. Prove that PA = PB + PC.

What is confusing me is the part

smallerarc BC of the cirumcircle of the triangle ABC

If ABC is an equilateral triangle, why would the arc BC be smaller than the arcs AB or AC? I would think that all the arcs would be equal. What the hey? What am I missing here?

Any help is appreciated.

Thankyou.