Geometry Help

  • Thread starter EggNest
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  • #1
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Hello everyone,

I need help with a couple of problems, right now I'm focusing on number 25.

http://img24.exs.cx/img24/2291/probs.gif

Also, if any of you have time, could you please tell me if I have missed any so far. Thanks.

22. A= 3768.2 units^2
23. A= 25.3 units^2
24. A= 5.4 units^2

And now if I could just get some help with the others...
 

Answers and Replies

  • #2
arildno
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Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
 
  • #3
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arildno said:
Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
I need help going about finding the lenght of the sides
 
  • #4
arildno
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Sure enough, but:
1) You've got a square, right?
So, how does then the vertical side compare in length to the horizontal side?
2) Try to set up Pythagoras' theorem with the diagonal as the hypotenuse..
 
  • #5
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The lenght of all the sides would be 7.5 sqrt(2) right?
 
  • #6
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We have C from Pythagoras' therom
[tex] a^2 + b^2 = c^2 [/tex]

however for a square
[tex] a=b [/tex]

so
[tex] a^2 + a^2 = c^2 [/tex]
[tex] 2a^2=c^2 [/tex]

[tex] 2a^2=15^2 [/tex]
[tex] 2a^2=225 [/tex]


since area of a square is just a*b and a=b
area equals a*a or a^2 so divide the two out
[tex] a^2=\frac{225}{2} [/tex]
 
  • #7
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I believe 22 is wrong
23 is right rounded
24 is right rounded
 
Last edited:
  • #8
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22. by law of sines

[tex]\frac {73}{\sin{\theta}}=\frac{x}{\sin{\theta}} [/tex]

therefore must also be 73
73*73*.5 = 2664.5
 

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