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Geometry of circle

  1. Oct 15, 2004 #1
    AD and BD touch the circule at points A and B
    AC is parallel to BD
    prove that:

    1. DF^2 = AF*EF
    2. BF = DF

    its obvious that BF^2 = EF * AF i tried proving that DF = FB but with no luck.

    edit: i uploaded the wrong picture earlier, terribly sorry i have so many of them :smile:

    Attached Files:

    Last edited: Oct 15, 2004
  2. jcsd
  3. Oct 16, 2004 #2
    anyone? :uhh:
  4. Oct 16, 2004 #3
    I cannot see the image so I cannot help you out. If you are still stuck a faster way may be to send the image in an email and I could help you out then.
  5. Oct 17, 2004 #4
    The attachment if you see is yet to be approved ....

    -- AI
  6. Oct 17, 2004 #5
    never mind guys i managed to solve it, thanks anyway :smile:
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