Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Geometry of discriminants

  1. Aug 14, 2007 #1


    User Avatar
    Science Advisor
    Homework Helper
    2015 Award

    consider a field k and the affine n space Y = k^n, whose coordinates a1,...,an parametrize monic polynomials over k. and over it consider the space S of solutions of those polynomials, i.e. S = {(a,x): where a = (a1,...,an) is a polynomial, and (x1,...,xn) are the roots of a lying in an algebraic closure K of k}.

    thus S is a subset of k^n x K^n.

    Let D in k^n be th zero locus of the discriminant formula of polynomials of degree n, so that a is in D if and only if there are fewer than n distinct roots of the polynomial a.

    Then, since the roots of each a are ordered, the degree of the map S--->Y is n!, but there are fewer than n! preimages precisely of the points a of D.

    Now consider the map S-->>X from S onto a subspace X of k^n x K, sending (a,x1,...,xn) to (a,x1). Thus X is the space of all pairs (a,x) where x is a root of a. thus we have maps S-->X-->Y where the first (left) map has degree (n-1)! and the second (right) map has degree n.

    Both maps S-->Y and X-->Y have the same discriminant locus D in Y. Then map S-->Y is the normal closure of the map X-->Y, in the sense that this is true of the induced map via pulback of functions, on their function fields.

    Moreover the group of deck transformations of S should presumably equal the Galois group of this normal field extension, and in the complex case. also the monodromy representation of the fundamental group.

    Now in the general case, this Galois group should still be S(n), but what happens if we focus on one point a, i.e. one polynomial. It would be nice to obtain the galois group of this polynomial from the general one.

    supose we take the ring k[X1,...,Xn] of the space Y, and the maximal ideal m corresponding to the point a and localize at it, getting k of course. upstairs we have the ring of S i guess, and can consider all maximal ideals of that ring which pull back to m, via the ring inclusion of k[Y] into k.

    now what? I suppose we want to consider the galois representation of the big galois group, no wait. we want some subgroup of the general group S(n). Maybe we should consider those automorphisms of the field k(S) that what? preserve the ring k? or that preserve one of the ideals over m?

    hmmmmm.... how do we get the Galois group of a from this geometry? I think it has something to do with "inertia groups" for those who know this stuff.

    This is the level of galois theory one gets from Lang, as contrasted with other books, like mine.
  2. jcsd
  3. Aug 14, 2007 #2

    Chris Hillman

    User Avatar
    Science Advisor

    You have a book on Galois theory? Do tell!
  4. Aug 17, 2007 #3


    User Avatar
    Science Advisor
    Homework Helper
    2015 Award

    just my webnotes from my courses.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Geometry of discriminants
  1. Prime Geometry (Replies: 11)

  2. N-spherical geometry (Replies: 1)