ABC is an equilateral triangle with sides of 2 cm. BC is extended its own length to point D and point E is the midpoint of AB. ED meets AC at F. Find the area of quadrilateral BEFC in square centimeters in simplest radical form. Show all work and clearly label figure(s).
The Attempt at a Solution
I could solve for the area of BEFC by making AF = 2-x and FC = x, but it's really convoluted and messy. Is there a simpler way of finding BEFC?
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