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Main Question or Discussion Point
In [tex] \bigtriangleup ABC , AB = BC[/tex] and [tex]CD[/tex] bisects angle C.
If [tex]y = \frac{1}{3}x[/tex] then z = ....

Ok. I've tried to make a bunch of substitutions for each of the angles and I can't seem to solve any for z.
I have found these two equations:
[tex] y + z + c = 180[/tex]
and
[tex] x + z + \frac{c}{2} = 180[/tex]
I know I can make substitutions/variants of these, but I still am stuck.
Any help is appreciated.
Jameson
If [tex]y = \frac{1}{3}x[/tex] then z = ....

Ok. I've tried to make a bunch of substitutions for each of the angles and I can't seem to solve any for z.
I have found these two equations:
[tex] y + z + c = 180[/tex]
and
[tex] x + z + \frac{c}{2} = 180[/tex]
I know I can make substitutions/variants of these, but I still am stuck.
Any help is appreciated.
Jameson
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