(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(a) Find the vector equation of the plane through the points (2,−1, 0) and (−5,−3, 1)

that is parallel to the line joining the points (3, 5,−1) and (0, 3,−2).

(b) Find the parametric equations of the straight line though the origin that is perpendicular

to this plane, and find where it intersects the plane.

2. Relevant equations

[tex]\hat{n} \cdot (r~-~r_{0}) = 0[/tex]

3. The attempt at a solution

Ok, I found two vectors, on joining the points(2,−1, 0) and (−5,−3, 1)and another joining the points(3, 5,−1) and (0, 3,−2), seeing as they are parallel they will share the same normal vector [tex]\hat{n}[/tex].

Then using [tex]\hat{n} \cdot (r~-~r_{0}) = 0[/tex] withrbeing (-5,-3, 1) and [tex]r_{0}[/tex] being (2,-1,0). To get the vector form of the equation plane.

but I am not exactly sure what points to use at this stage.

and I haven't attempted b as yet.

thanks!

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# Homework Help: Geometry question in 3 space.

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