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Geometry question

  1. Oct 6, 2006 #1
    ABC is an equilateral triangle with an area of 1 square cm.
    C' is the middle of [AB].

    i have to prove that AC^2 = 4 * sqrt(3) / 3

  2. jcsd
  3. Oct 6, 2006 #2
    use s = (a+b+c)/2 and area = {s*(s-a)*(s-b)*(s-c)}^2
    where a = b = c = x (say)
  4. Oct 7, 2006 #3
    i know this aint helping but since the question is also on triangle can i ask how u prove ratio theorm?
  5. Oct 7, 2006 #4
    ratio theorem ?? as in simillar triangles ??
  6. Oct 7, 2006 #5
    Write CC' (triangle height) in terms of length AC, then solve using triangle area equation.
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