1. Prove the property of exterior angle bisectors discussed in class. Given triangle ABC and point D on line AB such that CD bisects the exterior angle at C, then BD/AD=BC/AC. The only thing I can compute about this problem is the Property of Exterior Angle, but I don't know how to apply it to the problem. Exterior Angle is the angle between any side of a shape, and a line extended from the next side. <-- That's is all I understand. Help on where to start this problem out with. Thanks.