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Geometry Question

  1. Sep 28, 2008 #1
    1. Prove the property of exterior angle bisectors discussed in class. Given triangle ABC and point D on line AB such that CD bisects the exterior angle at C, then BD/AD=BC/AC.

    The only thing I can compute about this problem is the Property of Exterior Angle, but I don't know how to apply it to the problem.

    Exterior Angle is the angle between any side of a shape, and a line extended from the next side. <-- That's is all I understand.

    Help on where to start this problem out with.

  2. jcsd
  3. Sep 28, 2008 #2


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    Hi Chemistry101! :smile:

    You need to find (ie make) a similar triangle somewhere.

    Hint: draw a line through D parallel to BC :smile:
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