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Find a scalar equation that passes through the points (3,2,3), (-4,1,2) and (-1,3,2).

What I did was put that into the vector equation form, using (3,2,3) as a position vector, resulting in:

r=(3,2,3) +t(-7,-1,-1) + s(-5,2,0)

Then I found the cross product of the directional vectors and went from there, but my final answer was different then the one in the text book. Can someone tell me what I did wrong please?

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# Geometry Scalar Equation Help

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