- #1

wubie

Hello,

I am not sure how to interpret this question:

So what do I have then? Lines AB and CD which intersect at P where P is not between A and B but P is between C and D? (Why don't they just draw a diagram? @#$!@#$!@#$%!#$!#$!!!!). In fact, is it even possible to have a cyclic quad. if P is between CD and not between AB? I can only see a cyclic quad. happening if P is not between both AB and CD.

[?]

Opinions on the question would be appreciated. Thankyou.

I am not sure how to interpret this question:

Now should I assume that because it WAS explicitly stated that P is not between A and B and that it WAS NOT explicitly stated P is not between C and D that in fact P IS between C and D? (Hope you can follow that).Lines AB and CD intersect at a point P, where P is not between A and B. Show that if (PA)(PB) = (PC)(PD), then ABCD is a cyclic quadrilateral. [Note: The notation (XY) is used to represent the directed distance from X to Y.]

So what do I have then? Lines AB and CD which intersect at P where P is not between A and B but P is between C and D? (Why don't they just draw a diagram? @#$!@#$!@#$%!#$!#$!!!!). In fact, is it even possible to have a cyclic quad. if P is between CD and not between AB? I can only see a cyclic quad. happening if P is not between both AB and CD.

[?]

Opinions on the question would be appreciated. Thankyou.

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