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One of Jupiter's moons has a mass of 2.2x10^23kg and radius of 4600km. How high above the surface of the moon should a satellite of mass 112kg be so that it undergoes geosynchronous orbit about the moon? The rotational period of the moon is 0.7402 days.

So, I used T = [2*pi*(4600-r)^(3/2)] / [root (Gmp)], where mp is mass of planet (in this case the moon being orbited) and G is 6.67x10^-11. I converted the period into seconds, whereby 0.7402 days is 17.7648 hours, which is 63953.28s. I've also converted 4600km into 4,600,000m and kept mass in kilograms.

I plug in the numbers and keep getting 7.699x10^15m, which isn't correct. I'm not sure of the correct answer however, would just appreciate a shove in the right direction.

-Twiztidmxcn